N/4=3,n^-1=

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Solution for N/4=3,n^-1= equation: 



/4=3.N^-1=

We move all terms to the left:

/4-(3.N^-1)=0

We get rid of parentheses

-3.N^+1+/4=0

We multiply all the terms by the denominator


-(3.N^)*4+1*4+=0

We add all the numbers together, and all the variables

-(3.N^)*4=0

We multiply parentheses

-12N=0

N=0/-12

N=0

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